Solve basic linear equations in KS3 algebra. Use inverse operations to isolate the variable and check solutions by substitution with clear, step by step working.
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You can find more about this topic by visiting BBC Bitesize - Equations
You must have one expression on one side of the equals sign and another expression on the other side. The two sides must share the same value. If one side equals 56 then the other side must also equal 56
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Either the expressions balance and it is an equation or the expressions don't balance and it isn't an equation!
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A 'solution' is what you are looking for when trying to solve an equation
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When + 4 crosses over to the other side of the equals sign it must be changed to - 4
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In the correct answer, the expressions on either side of the equals sign are not the same value and therefore it is not an equation
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You must firstly have ascertained that x = 12
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Everything was going fine until the last item! To be correct, the last item would need to be x = 1
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(8 x 5) + (8 x 8) = 40 + 64 = 104
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To correct the equation it should read 2a = 6 - 2. All of the above leads us to the conclusion that a = 2
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You can work this one out by trial and error. 23 = 8 so is too low. 43 = 64 so is too high. Therefore the answer must be between 2 and 4 so it hast to be 3
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