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Handling Data (Difficult)
This quiz is all about cycling to school!

Handling Data (Difficult)

Handling data helps you understand complex information and spot trends. In 11 Plus Maths, this includes averages, graphs, and probability for deeper reasoning skills.

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Fascinating Fact:

The average rainfall in London is about 600 millimetres per year, but sometimes the data forgets about umbrellas.

In 11 Plus Maths, pupils work with data sets to calculate averages, compare results, and interpret charts. They also explore how probability and statistics help explain patterns in the real world.

  • Statistics: The study of data, including how it is collected, analysed, and interpreted.
  • Mean: The total of all numbers divided by how many numbers there are, also called the average.
  • Probability: The likelihood that a particular event will happen, shown as a fraction, decimal, or percentage.
What types of data are studied in 11 Plus Maths?

Students learn to handle numerical and categorical data, draw and interpret graphs, and calculate averages such as mean, median, and mode.

What is the difference between mean, median, and mode?

The mean is the average, the median is the middle value, and the mode is the number that appears most often in a data set.

How is probability linked to handling data?

Probability helps make predictions based on data. For example, it can be used to estimate the chance of certain outcomes in experiments or events.

1 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
What is the range of the given data?
8
10
7
2
Range = highest value - lowest value = 10 - 2 = 8
2 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
What is the mean of the given data?
6.4
9
6
8
Mean = (the sum of the data values) ÷ the number of data values. The sum of the data values = 9 + 2 + 4 + 5 + 6 + 9 + 10 = 45. The number of data values = 7 ? mean = 45 ÷ 7 = 6.429 = 6.4 (1 decimal place)
3 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
What is the mode of the given data?
odd
6
9
even
The mode is the data value that occurs most often: there are two nines
4 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
What is the median of the given data?
10
6
2
4
The median is the middle value of the data: you have to arrange the data in order BEFORE you can find it: 2, 4, 5, 6, 9, 9, 10. You have seven values, so the median is the 4th value = 6. It is usually best to arrange the data in ascending order. DON'T make the mistake of giving the median the value of its position: in this case 4 because it is the 4th value
5 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
How many of Christine's friends took part in the survey?
45
8
6
7
You have seven data values: each value corresponds to one person. DON'T make the mistake of calling the sum of the data values the number of people: it is NOT 45
6 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
Christine decided to include one more friend in her survey. If that friend hadn't cycled to school in the last month, how would that affect the latest month's value of the 'mean'?
It would lower the value of the 'mean'
It wouldn't affect the value of the 'mean' because the number of times she has cycled to school = 0
There isn't enough information to answer this question
It would increase the value of the 'mean'
Just because something is zero, it doesn't mean that it isn't important. Mean = (the sum of the data values) ÷ the number of data values. The sum of the data values = 0 + 9 + 2 + 4 + 5 + 6 + 9 + 10 = 45. So '0' won't affect the sum BUT the number of data values now = 8 because you have an extra person ? mean = 45 ÷ 8 = 5.63 = 5.6 (1 decimal place)
7 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
How many people cycled to school the same number of times?
18
9
2
0
9 repeats itself twice: so 2 people cycled to school the same number of times
8 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
How many people cycled to school more times than the mean number of times (before the extra person was included)?
3
4
2
5
The mean was 6.4: only three values > 6.4. You can't include the person who cycled 6 times because 6 < 6.4. D'oh!
9 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
Which of the following statements is correct?
The mean is always one of the data values
The mean is sometimes one of the data values
The mean is never one of the data values
The mean is never negative
A mean = 6.4 shows you that it doesn't have to be one of the data values, but it could be, e.g. the mean of the data set 1, 2, 3 is 2 which is equal to the second value
10 .
This question is based on the following data set which represents the number of times that Christine's friends cycled to school: 9, 2, 4, 5, 6, 9, 10.
Why does the data have to be ordered to calculate the median?
It makes the data set appear tidier
They don't have to be ordered
So that you know how many data values you have
If you don't order the data values, your answers will usually be different each time
Arrange the given data values in different orders: you will soon see that you get different medians most of the time, e.g. in the arrangement 6, 2, 10, 9, 9, 5, 4, the median = 9. In maths, you MUST strictly follow definitions to the letter - or you will get wrong answers!
Author:  Frank Evans (Specialist 11 Plus Teacher and Tutor)

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